The lengths of human pregnancies are normally distributed with a mean of 268 day & a standard deviation of 15 days. What is the probability that a pregnancy last at least 300 days?

The probability that a pregnancy last at least 300 days is 0.01659Step-by-step explanation:The formula of z-score is z = (x - μ)/σ, whereμ is the meanσ is the standard deviationx is the scoreThe lengths of human pregnancies are normally distributed with a mean of 268 day & a standard deviation of 15 days∴ μ = 268 days∴ σ = 15 daysWe need to find the probability that a pregnancy last at least 300 days∵ At least means greater than or equal∴ x ≥ 300 daysFor probability that x ≥ 300 find the z-score and use the normal distribution table to find the area to the right of the z-score∵ z = (x - μ)/σ∴ [tex]z=\frac{300-268}{15}[/tex]∴ z = 2.13By using the normal distribution table of z-score ∵ The area (to the left of z-score) corresponding to z-score of 2.13    is 0.98341∵ We need the area to the right of z-score∴ P(x ≥ 300) = 1 - 0.98341∴ P(x ≥ 300) = 0.01659The probability that a pregnancy last at least 300 days is 0.01659Learn more:You can learn more about probability in brainly.com/question/9178881#LearnwithBrainly