Solve for the indicate variables.1) h=vt - 2t^2; for v2) A=1/2(b1+b2) h; for b1

Solving [tex]h=vt-2t^2[/tex] for v gives [tex]v=\frac{h}{t}+2t[/tex]Solving [tex]A=\frac{1}{2}(b_1+b_2)}[/tex] for b1 gives [tex]b_1=2A-b_2[/tex]Step-by-step explanation:Given[tex]h=vt-2t^2[/tex]To solve for v, we have to isolate v on one side of the equation[tex]h=vt-2t^2\\Adding\ 2t^2\ on\ both\ sides\\h+2t^2=vt-2t^2+2t^2\\h+2t^2=vt\\Dividing\ both\ sides\ by\ t\\\frac{h+2t^2}{t}=\frac{vt}{t}\\v=\frac{h+2t^2}{t}\\v=\frac{h}{t}+\frac{2t^2}{t}\\v=\frac{h}{t}+2t[/tex]Given[tex]A=\frac{1}{2}(b_1+b_2)}[/tex]To isolate b1 we have to isolate b1So,[tex]A=\frac{1}{2}(b_1+b_2)}\\Multiplying\ both\ sides\ by\ 2\\2A=2*\frac{1}{2}(b_1+b_2)}\\2A=b_1+b_2\\Subtracting\ b_2\ from\ both\ sides\\2A-b_2=b_1+b_2-b_2\\b_1=2A-b_2[/tex]Hence,Solving [tex]h=vt-2t^2[/tex] for v gives [tex]v=\frac{h}{t}+2t[/tex]Solving [tex]A=\frac{1}{2}(b_1+b_2)}[/tex] for b1 gives [tex]b_1=2A-b_2[/tex]Keywords: Variable, Linear equationsLearn more about equations at:brainly.com/question/10760452brainly.com/question/10882895#LearnwithBrainly