A recent study indicates that the annual cost of maintaining and repairing a car in a town in Ontario averages 200 with a variance of 260. A tax of 20% is introduced on all items associated with the maintenance and repair of cars (i.e., everything is made 20% more expensive). Calculate the variance of the annual cost of maintaining and repairing a car after the tax is introduced.

Answer:374.4Step-by-step explanation: All items related to the maintenance are 20% more expensive, it means that each datum is 20% bigger including the average.The variance its a dispersion measurof the data and its calculated of this way:[tex]\sigma^{2} =\frac{1}{n} \sum\limits^n_{i=1} (x_{i}-\var{x})^2\\[/tex]Here n is the number of data, [tex]\var{x}[/tex] is the average and [tex]x_{i}[/tex] represent each datum. The increment in 20% in each parameter can be represented multiplying for 1.2, of this way[tex]\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1} (1.2x_{i}-1.2\var{x})^2\\[/tex]Factorizing the 1.2 we have:[tex]\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1} (1.2(x_{i}-\var{x}))^2[/tex][tex]\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1}1.2^{2} (x_{i}-\var{x})^2[/tex][tex]\sigma_{20\%}^{2} =\frac{1.2^{2}}{n} \sum\limits^n_{i=1} (x_{i}-\var{x})^2\\[/tex]That is:[tex]1.2^{2}\sigma^{2}=\sigma_{20\%}^{2}[/tex]The new variance is [tex]1.2^{2} \sigma^{2} =1.44*260=374.4[/tex]